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Averages Posts

How to Get Better Scores on the ACT with Approximation & Estimation

When you encounter a question on the ACT Math Test that you don’t know how to solve, what do you do? Even if your Math skills are strong, you’re likely to see at least a couple of challenging questions on the ACT Math Test. Sometimes doing the Math is not always the best way to get to the correct answer – a strategy like Picking Numbers or Backsolving can be preferable. You can also use Approximation & Estimation on difficult test questions; this is especially helpful when you’re running out of time, or for questions where there is no applicable formula. Let’s look at how we can use this in our Test Prep to get better ACT scores on Test Day.

Figure ABCDE was drawn on a grid of unit squares, with each vertex at the intersection of two grid lines. What is the area of the figure in square units?

A            19

B            23

C            25

D            27

E            33

 

Since there is no formula to solve for the area of this 5-sides figure, we know that Approximation will be our best strategy here. The way to find the area of this figure is to divide it into sections, first counting the full squares, then the half squares, then the pieces of square.

Whole squares (blue) = 19 full squares

Half squares (green) 2 = 1 full square

Grey pieces = 1 full square

Pink pieces = 1 full square

Purple pieces = 1 full square

Adding together all the areas gives a total of 23 square units. The answer is (B).

When you approximate, let the answer choices be your guide. If they are very close together, then you will need to be more accurate in your approximation. However, if the answer choices are markedly far apart, then by all means round to the nearest integer. Let’s look at a more challenging question:

In the table to the left, the amount of hardcover and paperback copies sold in a given year for novels L, M, N, P, and Q is provided. For which novel is the ratio of hardcover copies sold to the paperback copies sold the greatest for that year?

 

To solve this question it is MUCH faster to approximate by rounding each number to make the comparison easier. L is 800,000/1,300,000, or 8/13. Following the same logic of approximating and estimation: M is 3/6. N is 8/10. P is 3/7. Q is 10/25.

The question asks for the greatest ratio. Notice how 3/6, 3/7 and 10/25 are all around 50% or less. That leaves only 8/13 and 8/10. When the numerator stays the same and the denominator shrinks, we know we are getting a larger fraction of the total. Therefore, 8/10 is greater, so the answer is Title N.

For more practice looking at questions where Approximation & Estimation is an appropriate strategy, click on “Create Game” in the Grockit ACT lobby and make a custom game using only the skill tag “Approximation & Estimation.”

Find 2011 and 2012 ACT test dates here!

ACT Math: Averages

Averages, or arithmetic means, are likely to show up on the ACT Math section. Most of us know how to find the average, but the test will probably present average questions in a more complicated way.

Rather than present you with all the numbers in a set and ask you to find the average of those numbers, the ACT average problems will present you with various combinations of known and unknown information.

Before we begin, let’s go over some basic rules for finding averages. There are 3 numbers you want to know; they are related by the formula A= T / n, where A is average, T is the total sum of values, and n is the number of figures in a set.

1. The number of figures in a set (n). If I want to find the average of seven different test scores, then n=7.

2. The sum total of all the figures in a set (T). If the aforementioned scores are 80, 60, 70, 80, 95, and 90, 75, then T= 550.

3. The average of the figures in a set: (A)= T / N. In our example, A = 550 / 7 = 78.57.

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Finding Averages

SAT questions testing you on averages usually require you to realize that if the average of x numbers is n, then the sum of the x numbers is nx.  To illustrate with a numerical example: if the average age of 5 girls is 8, then the sum of their ages must be 5*8=40.

Knowing this principle is extremely important.  Let’s try and do a few questions together so that you can see how it works.

If the average grade of k students is 51 and the average grade of m students is 64 and the average of all the students is 54.  Then find k/m

  1. if the average of k students is 51, the total score of the k students = 51k
  2. if the average of m students is 64, the total score of the m students = 64m
  3. if the average score of all the students is 54, the total score of (k + m) students = 54(k + m)
  4. since the total score of k students + total score of m students = total score of all the students, then

51k + 64m = 54(k + m)

Most of you might get here and worry about getting k/m.  It’s actually not that difficult.  If you expand out the equation you get 51k + 64m = 54k + 54m.  Putting the k’s on one side and the m’s on the other, you get 10m = 3k.  Dividing both sides by m, then dividing by 3, you get k/m = 10/3

If a question tells you that in finding the average of a group of things, some values were measured wrongly, then here are the steps you should take.

  1. Given the average, find the total by multiplying the average by the number of things in the group.
  2. Subtract or add the incorrect amount from this total
  3. Divide by the number of things to find the actual average.

For example, if the average of John, Bob and Sally’s backpacks is 60lbs and the person weighing the bags forgot to set it to zero and added 10lbs to each of the measurements, what is the real average of the three bags?

  1. Find the total: 60lbs x 3 = 180 lbs
  2. Subtract the false weight that was added, which was 10lbs per bag, so 180lbs – 30lbs = 150lbs
  3. Divide 150lbs by 3 to find the actual average: 150 lbs / 3 = 50 lbs

The last type of averages question usually wants you to find a new average when the number of items has changed.  In this case, you have to find the total of all the items given, subtract the value of the items they don’t want, and divide by the remaining number of items to get the new average.

For example, if Adam, Bob and Chris has an average age of 12 and Chris is 8 years old, what’s the average age of Adam and Bob.  You would take 12*3 = 36 to find the total age of Adam, Bob and Chris.  Subtract Chris’ age 8 to get 28 and divide that by 2 (because its only Adam and Bob now) to get the new average of 14.

Conversely, the question could also look like this: Adam and Bob’s average age is 14.  When Chris’ age is added, the average is now 12.  How old is Chris?

  • Adam + Bob + Chris’ age = 12*3 = 36
  • Adam + Bob’s age = 14*2 = 28
  • So Chris’ age is 36 – 28 = 8

Remember, when dealing with averages, unless it’s a straightforward question that applies the definition of average, you usually need to find the total first, adjust it to what the question needs and then find the new average.