Perimeter questions on the GMAT are a subset of a subset — a small part of the geometry you will inevitably run into on the Quantitative side of the test. Perimeter is the distance around a geometric figure — from Ancient Greek περίμετρος, or “measure around” — and on the GMAT is just that: the sum of the side lengths of a two-dimensional figure (three dimensional figures have surface area instead). They are in the category of “easy things made hard”: it is not challenging to add up the side lengths of a polygon, even an irregular one, so the GMAT will force you to infer the information you need to answer the question. This is a short series of articles showing some of the ways different figures’ information can be used to create perimeter questions. Last time, I gave you this problem involving multiple shapes in the figure:

Note: figure not drawn to scale
The playing area for a certain outdoor game requires markings according to the figure shown. The ratio of AB:BC:AC is 3:4:5 ; O is the midpoint of the circle, R and Q are both points on the circle with center O and corners of square OBQR. If QB is 1/3 of AB and a person running in a straight line from Q to R travels 3√2 meters, approximately how many meters of paint are required to paint the playing area on a surface (assume the lines have negligible width)?
(A) 54π
(B) 97
(C) 72
(D) 67
(E) 45
Answer: (D) 67. How?
We know that the ratio of the lengths of the sides x of a square to its diagonal are the same as that of a 45:45:90 triangle: x:x:x√2. You could also use the Pythagorean Theorem, setting 3√2 as the hypotenuse, so (3√2)² = 2*(side length)², so 2s²=18, and s²=9, so the sides are 3 meters each. This is also the radius of the circle, so from here we can figure out:
Perimeter of circle: the circle’s radius is 3, and the perimeter (circumference) is 2πr, or 6π.
Perimeter of square: the square’s perimeter is 4s, or 12.
Perimeter of triangle: since QB is 1/3 of AB and QB = 3, AB = 9. Triangle ABC is in the 3:4:5 ratio, so the other sides are 12 and 15, respectively. 9 + 12 + 15 = 36.
Circle + square + triangle = 6π + 12 + 36 = 48 + 6π, or approximately 48+19 = 67 meters.







