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Lines on the GMAT: The Basics of Coordinate Geometry

By posted September 16, 2011

MBA admissions, and life in general, doesn’t always seem to follow a straight line. However in math, lines are one of the most fundamental building blocks and vital to practicing for the GMAT. In Euclidean geometry, a line is defined as having only one dimension: length. Lines appear on the GMAT in coordinate geometry in several ways, and various linear equations must be understood and applied on your GMAT practice questions to get even the most basic Geometry questions correct. It’s comforting to know that while MBA applications may be circuitous, the fundamentals of GMAT stay the same. Here are the need-to-know equations for better scores in GMAT Geometry!

Test your GMAT skills with this GMAT problem solving practice question!

The general equation for a line is: ax + by + c = 0 for all values (x,y) that are on that line. In this form, the slope is –a/b and the y-intercept is –c/b.

The most common equation for a line is called slope-intercept form: y = mx + b, for all values (x, y) on the line. Here m is the slope and b is the y-intercept.

A modified version of slope-intercept form is called point-slope form: y – y1 = m (x – x1) + b. This equation is helpful if you are given two points on the line, (x, y) and (x1, y1).

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GMAT Geometry Basics: Parallel Lines

By posted June 23, 2011

We can say that two lines are “parallel” if they never intersect and get neither closer nor farther away from one another. || is the symbol for parallel lines. In coordinate geometry, parallel lines have the same slope, but different x-intercepts.

Try this GMAT geometry practice question and test your skills today!

Parallel lines can be tested in either Problem Solving or Data Sufficiency and though the concept itself is relatively simple, the test questions presented can appear somewhat complex. Don’t make assumptions about lines that look parallel but may in fact not be. Let’s look at an example of how the “eyes can deceive” from GMATPrep:

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Beat the Coordinate Geometry Blues! – Part 2

By posted May 3, 2011

The standard equation for a parabola is y = ax2 + bx + c. In this equation c represents the y-intercept. A standard equation in which a variable is squared will never make a straight line.

Based on the figure, is this is the correct graph for the equation:  y = (x3 + x)/x ?


For a question like this, don’t get nervous if the equation given does not match the standard equation for a parabola. This equation simplifies to y = x2 + 1. We can see from the graph that the y-intercept is indeed 1. When we plug in the x-coordinates of the other two given points, we know this must be the correct equation. When in doubt, plug in!

The x-intercepts are also called the “roots” or “solutions” of a parabola. On the GMAT, parabolas will often be referred to as “functions” interchangeably. The x-intercepts can be found using the quadratic formula:

To find the number of x-intercepts a given parabola has, calculate what is called the discriminant:  or the information underneath the radical in the quadratic formula.

If the discriminant is positive, the parabola has two intercepts with x-axis; if it is negative there are no intercepts with the x-axis, and if the discriminant is equal to zero there is one intercept with the x-axis.

The vertex represents the maximum (or minimum) value of the function. Think of it as the starting point of the function.


The vertex of the parabola is located at point  for the standard equation. If you are given the standard equation, you can find the vertex and the x-intercepts.

The standard equation of a circle is (x – h)2 + (y – k)2 = r2 where (h, k) is the center point of the circle and r is the radius. For example, on test day you might see a circle plotted on a graph like so:

The question will ask you to find the equation of the circle. All we have to find is the center point (0, 4) and the radius (4), and then plug it into our equation.

(x – h)2 + (y – k)2 = r2

(x – 0)2 + (y – 4)2 = 42

(x)2 + (y – 4)2 = 16

Need more Coordinate Geometry help? Schedule a 1-hour lesson with one of Grockit’s GMAT tutors to focus only on coordinate geometry questions from the Grockit GMAT question bank, or check out the Coordinate Geometry questions in Grockit’s Academy, SAT, ACT, or GRE question banks for even more practice!

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Beat the Coordinate Geometry Blues! – Part 1

By posted April 28, 2011

Needing a solid coordinate geometry refresher? The best thing about studying online is that better scores are right at your fingertips. Review these fundamentals and you’ll soon be flying through the GMAT Geometry test questions!

There are two main equations for straight lines. One form looks like:
For an equation that looks like this the slope is and the y intercept is

For example, in the equation 2x + 3y + 6 = 0, the slope is -2/3 and the y-intercept is -2. The second equation is called slope-intercept form and looks like:   Here m is the slope and b is the y-intercept.

Distance Formula =     Use this to find the distance between two points.

Midpoint Formula =

Use this to find the midpoint between two points (notice how you are essentially finding the average of the x-coordinates and the average of the y-coordinates).

Slope = Rise / Run = Change in y / Change in x

Slopes can be positive, negative, zero, or undefined. Positive slopes tilt to the right. Negative slopes lean to the left. A line with a slope of zero is exactly horizontal. The line neither goes up nor goes down as x increases, which is why it has a 0 slope. Vertical lines have undefined slopes. When the two x coordinates are the same, their difference is zero. The slope calculation would leave a 0 in the denominator, which is called “undefined.”

As long as you know any two points on a line, you can find the slope. A line that passes through the origin must have (0,0) as one of its points. Remember that parallel lines have the same slope, and perpendicular lines have negative reciprocal slopes.

Points of intersection can be found by setting two lines equal. What is the point of intersection between the lines y = 2x – 1 and y = -1/2x + 4? Here’s a quick three-step solution:

  1. Put both lines in slope-intercept form. (These example equations are already in slope-intercept form).
  2. Set them equal & solve for x.

2x – 1 = -1/2x + 4

2.5x – 1 = 4

2.5x = 5

x = 2

3.   Plug x back in to either equation to find y.

y = 2x – 1

y = 2(2) – 1

y = 4 – 1

y = 3

The point of intersection will be (2,3). Check out Part 2 for parabolas and circles!

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